1.

A person lent a sum of Rs. 9000 on simple interest at 10% for 3 years. Find the difference in interest received by him, if he had lent the same sum on compound interest at 20% for 2 years.1). Rs. 19602). Rs. 11603). Rs. 12604). Rs. 2700

Answer»

Given,

Principal = 9000, Rate% = 10% and Time = 3 years

We KNOW that,

SIMPLE interest = (P×R×T)/100

⇒ SI = (9000×10×3)/100 = 2700

At compound interest,

$(Amount = P{\left[ {1 + \frac{{r\% }}{{100}}} \right]^{time}})$

$(Amount = 9000 \times {\left[ {1 + \frac{{20}}{{100}}} \right]^2})$

⇒ Amount = 12960

⇒ CI = Amount - Principal

⇒ CI = 12960 - 9000 = 3960

⇒ Difference of interest = CI - SI = 3960 - 2700 = 1260

Hence, 1260 will be the answer.

 



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