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A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 ms^(-2), what would be the reading of the weighing scale ? (g = 10 ms^(-2)) |
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Answer» SOLUTION :m= 15kg , g =10 `m/s^(2)` accelerationof lift= 9`m//s^(2)` Whenliftdescend(moves in downwarddirectionwithaccelerationof `9m//s^(2))` `=10 - 9 = 1 m//s^(2)` Apparentweightof person `R= mg ` `=50 xx 1` `=50 N` Readingof weighingscale `(R )/( g ) = (50)/( 10) = 5 KG` |
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