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| 1. |
A person of mass 60mg is in a lift The change in the apparent weight of the person when the lift moves up with acceleration of ms^(-2) and the down with an acceleration of 2ms^(-2) is (take g =10 m//sec^(2)) . |
| Answer» Solution :`w_(1) =m(G +a),w_(2) =MG(g -a)` | |