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A person on tour has Rs. 4200 for his expenses. If he extends his tour for 3 days, he has to cut down his daily expenses by Rs. 70. Find the original duration of the tour. |
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Answer» Let the original duration of the tour be x days. Then, `(4200)/(x)-(4200)/((x+3))=70` `implies" "4200xx[(1)/(x)-(1)/((x+3))]=70implies((x+3)-x)/(x(x+3))=(70)/(4200)` `implies" "x(x+3)=180impliesx^(2)+3x-180=0` `implies" "x^(2)+15x-12x-180=0impliesx(x+15)-12(x+15)=0` `implies" "(x+15)(x-12)=0impliesx+15=0" or "x-12=0` `implies" "x=-15" or "x=12` `implies" "x=12" "[because" number of days cannot be negative"].` `:." "` original duration of the tour is 12 days. |
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