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A person standing between two parallel hills fires a gun and hears the first echo after t_(1) sec and the second echo after t_(2) sec. The distance between the two hills is |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>(t_(1)-t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))/(2)`<br/>`(v(t_(1)t_(2)))/(2(t_(1)+t_(2)))`<br/>`v(t_(1)+t_(2))`<br/>`(v)/(2)(t_(1)+t_(2))`</p>Solution :Distance b/w <a href="https://interviewquestions.tuteehub.com/tag/man-1085541" style="font-weight:bold;" target="_blank" title="Click to know more about MAN">MAN</a> and hill 1, `d_(1)= (vt_(1))(2)` <br/> Distance b/w man and hill 2, `d_(2)= (vt_(2))(2)` <br/> Distance b/w the two hills, `d =d_(1)+ d_(2)` <br/> `d= (v(t_(1)+t_(2)))/(2)`</body></html> | |