1.

A person standing between two parallel hills fires a gun and hears the first echo after t_(1) sec and the second echo after t_(2) sec. The distance between the two hills is

Answer»

`(V(t_(1)-t_(2)))/(2)`
`(v(t_(1)t_(2)))/(2(t_(1)+t_(2)))`
`v(t_(1)+t_(2))`
`(v)/(2)(t_(1)+t_(2))`

Solution :Distance b/w MAN and hill 1, `d_(1)= (vt_(1))(2)`
Distance b/w man and hill 2, `d_(2)= (vt_(2))(2)`
Distance b/w the two hills, `d =d_(1)+ d_(2)`
`d= (v(t_(1)+t_(2)))/(2)`


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