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A person takes 4 tests in succession. The probability of his passing the first test is p, that of his passing each succeeding test is p or p/2 depending on his passing or failing the preceding test, Find the probabilty of his passing just three tests. |
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Answer» SOLUTION :Probability of passing just in 3 tests `=p^3(1-p)+(p^3(1-p))/2XX3` `=(p^3(2-2p+3-3p))/2` `=(p^3(5-5p))/2=5/2p^3(1-p)` |
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