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A person walks up a stationary escalator in time t1. If he reamains stationary on the escalator, then it can take him up in time t_(2). How much time would it take him to walk up the moving escalator? |
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Answer» Solution :LET L be the length of escalator. Speed of MAN w.r.t. escalator is `v_(me)=(L)/(t_(1))`. Speed of escalator `v_(e)= (L)/(t_(2))`. Speed of man with RESPECT to ground would be `v_(m)=v_(me)+v_(e)=L((1)/(t_(1))+(1)/(t_(2)))` `:. "The desired time is" t = (L)/(v_(m))=(t_(1)t_(2))/(t_(1)+t_(2))` |
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