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A person walks up a stationary escalator in time `t_(1)`. If he remains stationary on the escalator, then it can take him up in time `t_(2)`. How much time would it take for him to walk up the moving escalator? |
Answer» Let `L` be the length of escalator. Speed of man w.r.t. escalator is `V_(ME)=L/t_(1)` Speed of escalator `v_(E)=L/t_(2)` Speed of man with respect to ground would be `V_(M)=V_(ME)+V_(E)=L(1/t_(1)+1/t_(2))` `:.` The desired time is `t=L/v_(M)=(t_(1)t_(2))/(t_(1)+t_(2))` |
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