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A person walks up a stationary excalator in time tl. If he remains stationary on the escalator, then it can take him up in time t_(2). How much time would it take him to walk up the moving escalator? |
Answer» <html><body><p></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> be the length of ascalator. <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of man w.r.t esacalator is `v_(me)=(L)/(t_(1))`. Speed of escalator `v_(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>)=(L)/(t_(2))` <br/> Speed of man with respect to <a href="https://interviewquestions.tuteehub.com/tag/ground-1013213" style="font-weight:bold;" target="_blank" title="Click to know more about GROUND">GROUND</a> would be `v_(m)+v_(me)+v_(e)=L((1)/(t_(1))+(1)/(t_(2)))` <br/> `:.` The desired time is `t=(L)/(v_(m))=(t_(1)t_(2))/(t_(1)+t_(2))`</body></html> | |