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A person who is sitting at a distance of 400 m from a source of sound is listening to a sound of 600 Hz. Find the time period between successive compressions from the source? |
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Answer» Distance of the observer = 400 m Frequency of sound n = 600 Hz Let velocity of sound be v = 330 \(\frac{m}{s}\) Wavelength λ = \(\frac{v}{n}\) = \(\frac{330}{600}\) = 55 × 10-2 = 0.55 m Distance between two successive compressions is \(\frac{λ}{2}\) Time period successive compressions is = \(\frac{1}{\frac{λ}{2}}\) = \(\frac{2}{λ}\) = \(\frac{2}{0.55}\) T = \(\frac{2}{0.55}\) = 3.6363 second Time period = 3.6363 second. |
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