1.

A petrol engine consumes 5 kg of petrol per hour. If the power of engine is 20 kilo watts and the calorific value of petrol is 11×103 k cal per kg, calculate the efficiency of the engine.

Answer»

Pin = 11*103 kcal/kg * 5 kg/hr

Pin = 55*103 kcal/hr

unit conversion:

1 kcal/hr = 0.001163 kW

Pin = 55*103 kcal/hr * 0.001163 kW /kcal/hr

Pin = 63.965 kW

Power Out:

Pout = 20 kW

Efficiency:

Eff = Pout / Pin

Eff = 20 kW / 63.965 kW

Eff = 0.3127 or 31.27%



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