Saved Bookmarks
| 1. |
A petrol engine consumes 5 kg of petrol per hour. If the power of engine is 20 kilo watts and the calorific value of petrol is 11×103 k cal per kg, calculate the efficiency of the engine. |
|
Answer» Pin = 11*103 kcal/kg * 5 kg/hr Pin = 55*103 kcal/hr unit conversion: 1 kcal/hr = 0.001163 kW Pin = 55*103 kcal/hr * 0.001163 kW /kcal/hr Pin = 63.965 kW Power Out: Pout = 20 kW Efficiency: Eff = Pout / Pin Eff = 20 kW / 63.965 kW Eff = 0.3127 or 31.27% |
|