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A photon of light with wavelength 700 nm has energy E. A photon of light of what wavelength would correspond to energy 2E ?

Answer» Correct Answer - 350 nm
`E=(hc)/(lambda) or E prop (1)/(lambda) `(`:.` h and c are both constants)
`(E_(1))/(E_(2))=(lambda_(2))/(lambda_(1))` Now `lambda_(1)=700 nm, E_(1)=E, E_(2)=2E , (E)/(2E) = (lambda_(2))/(700) or lambda_(2)=(700)/(2)=350 nm`.


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