A physical quantity is given by h=(Fv^2)/L is the force, v is the velocity and Lis the angular momentum. Find the dimensions of h.

A physical quantity is given by h=(Fv^2)/L is the force, v is the velo

1.	A physical quantity is given by h=(Fv^2)/L is the force, v is the velocity and Lis the angular momentum. Find the dimensions of h.
Answer» SOLUTION :`H=(Fv^2)/L[h]=([MLT^-2][LT^-1]^2)/[[ML^2T^-1]]=[M^0LT^-3]`