1.

A physical quantity is measured as Q = (2.1 pm 0.5) units. Calculate the percentage error in (1) Q^(2)(2)2Q

Answer»

Solution :`P = Q^(2)`
`(Deltap)/(p) = (2DeltaQ)/(Q) = 2 ((0.5)/(2.1)) = (1.0)/(2.1) = 0.476 , (Deltap)/(p) XX 100% = 47.6% = 48% , R = 2Q`
`(DeltaR)/(R) = (DELTAQ)/(Q) rArr (0.5)/(2.1) = 0.238`
`(DeltaR)/(R) xx 100% = 24%`


Discussion

No Comment Found