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A physical quantity is measured as Q = (2.1 pm 0.5) units. Calculate the percentage error in (1) Q^(2)(2)2Q |
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Answer» Solution :`P = Q^(2)` `(Deltap)/(p) = (2DeltaQ)/(Q) = 2 ((0.5)/(2.1)) = (1.0)/(2.1) = 0.476 , (Deltap)/(p) XX 100% = 47.6% = 48% , R = 2Q` `(DeltaR)/(R) = (DELTAQ)/(Q) rArr (0.5)/(2.1) = 0.238` `(DeltaR)/(R) xx 100% = 24%` |
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