A physical quantity P is given by p= [A^3.B^(2/3)]/[C^4.D^(1/2)] where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is

A physical quantity P is given by p= [A^3.B^(2/3)]/[C^4.D^(1/2)] where

1.	A physical quantity P is given by p= [A^3.B^(2/3)]/[C^4.D^(1/2)] where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is
Answer» c88cyyo HO 9u9hvyvy8ycy y8y 9Y 8Y Y8 cyyc88tcyc9cy99tct8cyc8cy9y9cyy 9hExplanation:OH no pv0ihig0iv0i0vivviivivivuctxtxtzhckbnolnkbkvucrzrzrz4boonojpjpjpjpjpjjoob