A physical quantity P is related to four observables a,b,c and d as follows: P = a^(3)b^(2)/(sqrtcd) The percentage errors of measurement in a,b, c and d are 1%, 3% , 4% and 2% respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?

A physical quantity P is related to four observables a,b,c and d as fo

1.	A physical quantity P is related to four observables a,b,c and d as follows: P = a^(3)b^(2)/(sqrtcd) The percentage errors of measurement in a,b, c and d are 1%, 3% , 4% and 2% respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>%, 3.8</body></html>