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A physical quantity `X` is defined by the formula `X=(IFv^(2))/(WL^(3))` where `I` is moment of inertia, `F` is force, `v` is velocity, `W` is work and `L` is length, the dimensions of `X` areA. `["MLT"^(-2)]`B. `["MT"^(-2)]`C. `["ML"^(2)"T"^(-3)]`D. `["LT"^(-1)]` |
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Answer» Correct Answer - B We knows, Dimensions of moment of inertia = `["ML"^(2)]` Dimensions of moment of force `F=["MLT"^(-2)]` Dimensions of moment of velocity `(v)=["LT"^(-2)]` Dimensions of moment of work `(W)=["ML"^(2)"T"^(-2)]` Dimensions of moment of length `(l)=["L"]` Here, Dimensions of `[X]=("Dimensions of "[IFv^(2)])/("Dimensions of "[WL^(3)])` `" "=(["ML"^(2)]["MLT"^(-2)]["LT"^(-2)]^(2))/(["ML"^(2)"T"^(-2)]["L"^(3)])` `(["M"^(2)"L"^(5)"T"^(-4)])/(["ML"^(-5)"T"^(-2)])=["MT"^(-2)]` |
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