A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The velocity acquired by the electron will be

A physicist was performing experiments to study the effect of varying

1.	A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The velocity acquired by the electron will be
Answer» <html><body><p>double in the <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> than in the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> case<br/>four times in the second case than in the first case<br/>same in both cases<br/>1.4 times in the second case than in the first case</p>Solution :K.E. of the electron in case `I = 1000 <a href="https://interviewquestions.tuteehub.com/tag/ev-976207" style="font-weight:bold;" target="_blank" title="Click to know more about EV">EV</a>` <br/> `= 1000 xx 1.602 xx 10^(-16) J = 1.602 xx 10^(-16)J` <br/> K.E. of the electron in case II = 2000 eV <br/> `= 2 xx 1.602 xx 10^(-16) J` <br/> `:. ((1)/(2) mv_(2)^(2))//((1)/(2) mv_(1)^(2)) = 2 or (v_(2)//v_(1))^(2) = 2` <br/> or `v_(2)//v_(1) = sqrt2 = 1.4`</body></html>