Saved Bookmarks
| 1. |
A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The velocity acquired by the electron will be |
|
Answer» double in the SECOND CASE than in the FIRST case `= 1000 xx 1.602 xx 10^(-16) J = 1.602 xx 10^(-16)J` K.E. of the electron in case II = 2000 eV `= 2 xx 1.602 xx 10^(-16) J` `:. ((1)/(2) mv_(2)^(2))//((1)/(2) mv_(1)^(2)) = 2 or (v_(2)//v_(1))^(2) = 2` or `v_(2)//v_(1) = sqrt2 = 1.4` |
|