1.

A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The velocity acquired by the electron will be

Answer»

double in the SECOND CASE than in the FIRST case
four times in the second case than in the first case
same in both cases
1.4 times in the second case than in the first case

Solution :K.E. of the electron in case `I = 1000 EV`
`= 1000 xx 1.602 xx 10^(-16) J = 1.602 xx 10^(-16)J`
K.E. of the electron in case II = 2000 eV
`= 2 xx 1.602 xx 10^(-16) J`
`:. ((1)/(2) mv_(2)^(2))//((1)/(2) mv_(1)^(2)) = 2 or (v_(2)//v_(1))^(2) = 2`
or `v_(2)//v_(1) = sqrt2 = 1.4`


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