1.

A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV In order to have half the velocity in the second case than in the first case, the potential applied should be

Answer»

0.5 KV
2kV
0.25 kV
0.75 kV

Solution :We WANT to have `(v_(2))/(v_(1)) = (1)/(2) " i.e., " ((1)/(2) mv_(2)^(2))/((1)/(2) mv_(1)^(2)) = (1)/(4)`
i.e., `("Potential applied in case II")/("Potential applied in case I") = (1)/(4)`
or Potential applied in case `II = (1)/(4) xx 1kV`
= 0.25 kV


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