InterviewSolution
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InterviewSolution
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A physicist works in a laboratory where the magnetic field is `2T`. She wears a necklace enclosing area `0.01 m^(2)` in such a way that the plane of the necklace is normal to the field and is having a resistance `R=0.01Omega`. Because of power failure, the field decays to `1T` in time `10^(-3)` seconds. The what is the total heat produced in her necklace?`(T=tesla)`A. 40 JB. 30 JC. 20 JD. 10 J |
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Answer» Correct Answer - D `t = 10^(-3) s, R = 10^(-2) Omega and A = 10^(-2) m^(2)` `e = (d phi)/(dt) = ((B_(1)-B_(2))A)/(dt)` `e = ((2-1)xx10^(-2))/(10^(-3)) = 10 V` `:.` The heat developed, `H = (V^2t)/R` `:. H = (10 xx 10 xx 10^(-3))/(10^(-2)) :. H = 10 J`. |
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