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A piece of copper having a rectangular cross section of 15.2 mm x 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain.Y_(Cu)=1.2 xx 10 ^(11) N//m^(2). |
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Answer» Solution :`Y= ("LONGITUDINAL stress")/("Longitudianal STRAIN")` `THEREFORE` ongitudinal strain `= ("Stress")/(Y) = (F)/(AY) = (F)/(l xx BXX Y)` `= (44500)/(15.2 xx 10 ^(-3) xx 19.1 xx 10 ^(-3) xx 1.2 xx 10^( + 11))=0.00127` `~~ 1.27 xx 10 ^(-3)` |
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