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A piece of copper of mass 106 g is dipped in a measuring cylinder containing water at 22 ml mark. The water rises to 34 ml mark. Find (a) volume of the copper piece (b) the density of copper. |
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Answer» (a) Volume of the copper piece,`V=34ml-22ml` `=12ml` `=12cm^3` (b) Density of copper, `d=("mass of copper piece"(M))/("volume of copper piece"(V))` `=(160g)/(12cm^3)=8.83(g)/(cm^2)` `=8.83xx1000(kg)/(m^3)` `=883(kg)/(m^3)` |
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