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A piece of ice (heat capacity `=2100 J kg^(-1) .^(@)C^(-1)` and latent heat `=3.36xx10^(5) J kg^(-1)`) of mass m grams is at `-5 .^(@)C` at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally when the ice . Water mixture is in equilibrium, it is found that 1 gm of ice has melted. Assuming there is no other heat exchange in the process, the value of m in gram is |
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Answer» Here, heat given is used to increase the temperature of the ice to `0^@ C` and to melt `1 gm` of ice. Given `m` is mass of ice in `gm`. :. `420 = (m xx 2100 xx 5 + 1 xx 3.36 xx 10^(5)) xx 10^(-3)` `rArr m = 8 gm`. |
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