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A piece of metal weighs 46g times g in air. It weighs 30g times g in a liquid of specific gravity 1.24 at 27^(@)C. At 42^(@)C, when the specific gravity of the liquid is 1.20, the weight of the piece immersed in it is 30.5g times g.Find the coefficient of linear expansion (alpha) of the metal. |
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Answer» SOLUTION :Mass of the displaced liquid at `27^(@)C` `""=46-30=16g` Volume of the displaced liquid at `27^(@)C, V_(27)=16/1.24 cm^(3)` Similarly volume of the displaced liquid at `42^(@)C`, `""V_(42)=(46-30.5)/1.20=15.5/1.20cm^(3)` So the volume of the PIECE at `27^(@)C " and " 42^(@)C` are `16/1.24cm^(3) " and " 15.5/1.20cm^(3)` respectively. Now, `V_(42)=V_(27){1+gamma(42-47)}` [where `gamma`= COEFFICIENT of volume expansion of the metal] or, `""15.5/1.20=16/1.24{1+gamma times 15} " or, " 1+15gamma=(15.5 times 1.24)/(1.20 times 16)` or, `"" 15gamma=1.001-1` or, `"" gamma=0.001/15=3alpha` `therefore` Coefficient of linear expansion of the metal, `"" alpha=gamma/3=0.001/45=2.2 times 10^(-5@)C^(-1).` |
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