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A piece of platinum wire has resistance of 2.5 Ω at 0 °C. If its temperature coefficient of resistance is 4 × 10-3/°C. Find the resistance of the wire at 80 °C. |
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Answer» Given: R0 = 2.5 Ω α = 4 × 10-3/°C = 0.004/°C T = 80 °C To find: Resistance at 80 °C (RT) Formula: RT = R0(l + αT) Calculation: From formula, RT = 2.5 [1+ (0.004 × 80)] = 2.5(1 + 0.32) RT = 2.5 × 1.32 RT = 3.3 Ω |
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