A piece of wire 48 cm long is bent to form arectangle whose length is

1.	A piece of wire 48 cm long is bent to form arectangle whose length is twice its width.Calculate its area.
Answer» Explanation: Solution; given, length of a wire = 48CM let the width of rectangle is X cm then,length= 2x cm perimeter of rectangle = 48cm now, perimeter = 2(I+b) 48 =2(2x+x) 48=23x 48/2=3x 24. = 3x x=8 cm length = 2x=28=16cm width =x=8 cm now, AREA= length width =168 =144cm^2 I hope it is helpful

A piece of wire 48 cm long is bent to form arectangle whose length is twice its width.Calculate its area.

Answer»

Explanation:

Solution;

given,

length of a wire = 48CM

let the width of rectangle is X cm

then,length= 2x cm

perimeter of rectangle = 48cm

now,

perimeter = 2*(I+b)

48 =2*(2x+x)

48=2*3x

48/2=3x

24. = 3x

x=8 cm

length = 2x=2*8=16cm

width =x=8 cm

now,

AREA= length *width

=16*8

=144cm^2

I hope it is helpful