A piece of wire is bent in the shape of a parabola y = kx^(2)(y-axis vertical) with a bead of mass 'm' on it. The bead can slide on the wire without friction. The wire is now accelerated parallel to the x-axis where the with an acceleration'a'. The distance of the new equilibrium position of the bead isa/(xgk) where the bead can stay at rest with respect to the wire from y-axis. The value of x' is

A piece of wire is bent in the shape of a parabola y = kx^(2)(y-axis v

1.	A piece of wire is bent in the shape of a parabola y = kx^(2)(y-axis vertical) with a bead of mass 'm' on it. The bead can slide on the wire without friction. The wire is now accelerated parallel to the x-axis where the with an acceleration'a'. The distance of the new equilibrium position of the bead isa/(xgk) where the bead can stay at rest with respect to the wire from y-axis. The value of x' is
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html>