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A piece of wood from an aechaeological sample has 5.0 counts "min"^(-1) per gram of C - 14, while a fresh sample of wood has a count of 15.0 "min"^(-1). If half-life of C-14 is 5770 years, the age of the archaeological sample is |
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Answer» 8,500 years Now, `t_(1//2) = 5770` years `lambda = (0.693)/(t_(1//2)) = (0.693)/(5770) "years"^(-1)` where , `lambda` = decay constant If age is t years, then `t = (2.303)/(lambda) log_(10) ("activity of the FRESH SAMPLE")/("activity of archaecological sample")` `implies t = 2.303 xx (5770)/(0.693) xx log_(10) 15/5` `implies t = 9149` years `~~ 9200` years (approx). |
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