1.

A piece of wood from an aechaeological source shows a C - 14 activity which is 60% of the activity found today. Calculate the age of the sample t_(1//2)for""_(6)^(14)C = 5770years).

Answer»

3515 years
300 YEAR
4253 year
4000 years

Solution :`LAMBDA = (0.693)/(5770) YR^(-1), t = (2.303)/(0.693//5770) "log" (100)/(60)`
`= 4253` years.


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