1.

A piece of wood of mass m is floating erect in a liquid whose density is p. If it is slightly pressed down and released, then executes simple harmonic motion. Show that its time period of oscillation is T = 2π\(\sqrt {(m/Agρ)}\)

Answer»

Spring factor of liquid(k) = Aρg 

Inertia factor of wood = m

Time period T = 2π = image 12

T =2π\(\sqrt {(m/Agρ)}\)



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