Saved Bookmarks
| 1. |
A piece of wood of mass m is floating erect in a liquid whose density is p. If it is slightly pressed down and released, then executes simple harmonic motion. Show that its time period of oscillation is T = 2π\(\sqrt {(m/Agρ)}\) |
|
Answer» Spring factor of liquid(k) = Aρg Inertia factor of wood = m Time period T = 2π = image 12 T =2π\(\sqrt {(m/Agρ)}\) |
|