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A piece of work can be done by 16 man in 8 days working 12 hours a day. How many men ar needed to complete another work,which is three times the first one, in 24n days working 8 hourse, a day? |
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Answer» Using the formula, `(M_(1)D_(1)H_(1))/(W_(1))=(M_(2)D_(2)H_(2))/(W_(2))` Let `W_(1)=x and W_(2)=3x` `M_(1)=16,H_(1)=12,D_(1)=8` `H_(2)=8,D_(2)=24` `:.(16xx8xx12)/(x)=(M_(2)xx24xx8)/(3x)` `rArrM_(2)=24` `:.` Requrired numbrer of men is 34 |
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