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A piece of work can be done by 16 men in 8 days working 12 hours a day. How many men are needed to complete another work, which is three times the first one, in 24 days working 8 hours a days ? |
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Answer» Using the formula,`(M_(1)D_(1)H_(1))/(W_(1))=(M_(2)D_(2)H_(2))/(W_(2))` Let `W_(1)=x` and `W_(2)=3x` `M_(1)`=16,`H_(1)`=12,`D_(1)`=8 `H_(2)`=8,`D_(2)`=24 `:. (16xx8xx12)/(x)=(M_(2)xx24xx8)/(3x)` `implies M_(2)=24` men. |
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