1.

A piece of zinc metal is dipped in a 0.1 M solution of zinc salt. The salt is dissociated to the extent of 20%. Calcualte the electrode potential of Zn^(2+)//Zn (Given E_(Zn^(2+)//Zn)^(@) = -0.77 volt

Answer»


Solution :`[Zn^(2+)]=0.1 xx 0.2 =0.02 M`
`Zn^(2+)+2E^(-) RARR Zn"(REDUCTION)"`
`E_(Zn^(2+)//Zn)=E_(Zn^(2+)//Zn)^(@)+0.0591/2 log_(10) [Zn^(2+)]`


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