1.

A pieceof stoneweight18gin water. 20 n in gerosence( relativedensityof kerosence= 0.8) .Find(I )massof stone- piece , (ii )volumeof stone- pieceand (iii )densityof stone- piece .

Answer»

Solution :InCGSsystem ,themagnitudesfo densityandspecificgravityare same.Morover , themagnitudesof massM expressedin unita andweightWexpressedin unitg- wtare same.
Letmassof stone= M , volume= V
`therefore ` WEIGHTOF samevolumeof water`= V xx 1 = V =`
Apparentlossofweightof stoneinwater,
Given, `M- V = 18`
similarlyin CASEOF kerosene`, M- 0.8V=200 `
Subtracting(1)from(2), we get
`0.2V=2 `
or , `V=(2)/(0.2) = 10cm^(3) `
subsitingin EQUATION(1)
`M-10= 18or ,M=28g `
density ofstone`=(M)/(v )= (28) /(10)= 2.8* CM ^(-3)`
`therefore ` densityof stone`=( M )/(v ) =(28) /(10)= 2.8g * cm ^(-3)`


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