1.

A pipe can fill a pool in 3 hours, due to leakage in the bottom, it takes \(3\frac{1}{2}\) hours to fill it. In what time the leakage will empty the pool?1. 12 hours2. 21 hours3. \(6\frac{1}{2}\) hours4. \(10\frac{1}{2}\) hours

Answer» Correct Answer - Option 2 : 21 hours

Given:

A pipe can fill a pool in 3 hours.

With leakage pool can be filled in \(3\frac{1}{2}\) hours

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Work done in 1 hour by the pipe = 1/3

Work done in 1 hour by leakage and pipe = 2/7

Work done by the leakage in 1 hour = (1/3) – (2/7)

⇒ (7 – 6)/21

⇒ 1/21

The leakage can empty the pool in 21 hours.



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