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A pipe can fill a pool in 3 hours, due to leakage in the bottom, it takes \(3\frac{1}{2}\) hours to fill it. In what time the leakage will empty the pool?1. 12 hours2. 21 hours3. \(6\frac{1}{2}\) hours4. \(10\frac{1}{2}\) hours |
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Answer» Correct Answer - Option 2 : 21 hours Given: A pipe can fill a pool in 3 hours. With leakage pool can be filled in \(3\frac{1}{2}\) hours Concept: If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank. Calculation: Work done in 1 hour by the pipe = 1/3 Work done in 1 hour by leakage and pipe = 2/7 Work done by the leakage in 1 hour = (1/3) – (2/7) ⇒ (7 – 6)/21 ⇒ 1/21 ∴ The leakage can empty the pool in 21 hours. |
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