A plane electromagnetic wave of wavelength `lambda` has an intensity I. It is propagating along the positive Y-direction. The allowed expression for the electric and magnetic fields ar given by : `vecE=sqrt((2I)/(in_(0)c))cos[(2pi)/(lambda)(y-ct)]hatk`,A. `vecB=+(1)/(c)E " veci` `vecE=sqrt((2I)/(in_(0)c))cos[(2pi)/(lambda)(y+ct)]hatk`,B. `vecB=(1)/(c)E " veci` `vecE=sqrt((I)/(in_(0)c))cos[(2pi)/(lambda)(y-ct)]hatk`,C. `vecB=(1)/(c)E " veci` `vecE=sqrt((I)/(in_(0)c))cos[(2pi)/(lambda)(y-ct)]hati`,D. `vecB=(1)/(c)E " veci`

A plane electromagnetic wave of wavelength `lambda` has an intensity I

1.	A plane electromagnetic wave of wavelength `lambda` has an intensity I. It is propagating along the positive Y-direction. The allowed expression for the electric and magnetic fields ar given by : `vecE=sqrt((2I)/(in_(0)c))cos[(2pi)/(lambda)(y-ct)]hatk`,A. `vecB=+(1)/(c)E " veci` `vecE=sqrt((2I)/(in_(0)c))cos[(2pi)/(lambda)(y+ct)]hatk`,B. `vecB=(1)/(c)E " veci` `vecE=sqrt((I)/(in_(0)c))cos[(2pi)/(lambda)(y-ct)]hatk`,C. `vecB=(1)/(c)E " veci` `vecE=sqrt((I)/(in_(0)c))cos[(2pi)/(lambda)(y-ct)]hati`,D. `vecB=(1)/(c)E " veci`
Answer» Correct Answer - A

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