1.

A plane isin level flight at constant speed and each of its two wings has an area of 25m^(2) If the speed of the air is 180/h over the lower wingand 234km/h over the upper wing suface , determine the plane's mass . (Take air density to be 1kgm^(-3)).

Answer»

<P>

Solution :Speed of air over lower WING `v_(1)=180km//`
`=(180xx1000)/(3600)`
`=50ms^(-1)`
and speed over the upper wing`v_(2)=234km//h`
`=(234xx1000)/(3600)`
`=65ms^(-1)`
Bernoulli.s equation,
`P_(1)+(1)/(2)rhov_(1)^(2)+h_(1)rhog=P_(2)+(1)/(2)rhov_(2)^(2)+h_(2)rhog`
but `h_(1)=h_(2)`
`thereforeP_(1)-P_(2)=(1)/(2)rho(v_(2)^(2)-v_(1)^(2))`
`=(1)/(2)xx1[65^(2)-50^(2)]`
`=(1)/(2)[4225-2500]`
`=(1)/(2)[1725]`
`thereforeP_(1)-P_(2)=862.5Pa`
RESULTANT force on wings `F=(P_(1)-P_(2))A`
`=862.5xx2xx25`
Two wings)
`=43125N`
Now , F=mg
`thereforem=(F)/(G)=(43125)/(9.8)`
`thereforem=4400.5kg`
`thereforem=4393kg`


Discussion

No Comment Found