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A plane isin level flight at constant speed and each of its two wings has an area of 25m^(2) If the speed of the air is 180/h over the lower wingand 234km/h over the upper wing suface , determine the plane's mass . (Take air density to be 1kgm^(-3)). |
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Answer» <P> Solution :Speed of air over lower WING `v_(1)=180km//``=(180xx1000)/(3600)` `=50ms^(-1)` and speed over the upper wing`v_(2)=234km//h` `=(234xx1000)/(3600)` `=65ms^(-1)` Bernoulli.s equation, `P_(1)+(1)/(2)rhov_(1)^(2)+h_(1)rhog=P_(2)+(1)/(2)rhov_(2)^(2)+h_(2)rhog` but `h_(1)=h_(2)` `thereforeP_(1)-P_(2)=(1)/(2)rho(v_(2)^(2)-v_(1)^(2))` `=(1)/(2)xx1[65^(2)-50^(2)]` `=(1)/(2)[4225-2500]` `=(1)/(2)[1725]` `thereforeP_(1)-P_(2)=862.5Pa` RESULTANT force on wings `F=(P_(1)-P_(2))A` `=862.5xx2xx25` Two wings) `=43125N` Now , F=mg `thereforem=(F)/(G)=(43125)/(9.8)` `thereforem=4400.5kg` `thereforem=4393kg` |
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