A plane P intersects lines L1, L2, L3 and L4 at A, B, C, D L1:x−32=y – InterviewSolution

1.	A plane P intersects lines L1, L2, L3 and L4 at A, B, C, D L1:x−32=y−31=z−32 L2:x−32=y−31=z2L3:x2=y−31=z2 L4:x2=y−31=z−32 then the minimum area of quadrilateral ABCD is ___.
Answer» A plane P intersects lines $L_{1}, L_{2}, L_{3} a n d L_{4}$ at A, B, C, D $L_{1} : \frac{x - 3}{2} = \frac{y - 3}{1} = \frac{z - 3}{2} L_{2} : \frac{x - 3}{2} = \frac{y - 3}{1} = \frac{z}{2} L_{3} : \frac{x}{2} = \frac{y - 3}{1} = \frac{z}{2} L_{4} : \frac{x}{2} = \frac{y - 3}{1} = \frac{z - 3}{2}$ then the minimum area of quadrilateral ABCD is ___.

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