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A plane passes through the points (1, 1, 1). If b, c, a are the direction ratios of a normal to the plane where a, b, c (a lt b lt c) are the prime factors of 2001, then the equation of the plane is: |
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Answer» `29x + 31y + 3z = 63` `b(x-1)+c(y-1)+a(z-1)=0` Now, `2001=3xx23xx29` `THEREFORE a lt b ltc rArr a = 3, b=23 and c=29` Substituting the VALUES of a, b, c in (i), we obtain `23x+26y+3z=55` as the equation of the required plane. |
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