1.

A plane progessive wave of frequency 25 Hz, amplitude 2.5 xx 10^-5 m and initial phase zero propagates along the negative x-direction with a velocity of 300 m//s. At any instant, the phase difference between the oscillations at two points 6 m apart the line of propagation is _____ and the corresponding amplitude difference is _____ m.

Answer»

Solution :`u = 300 m//s` and `N = 25`
`:. LAMDA = (u)/(n) =(300)/(25) = 12 m`
For a path difference of `lamda`, the PHASE difference is `2 pi`.
For a path difference of `6 m`, the phase difference is
`(2 pi xx 6)/(lamda) = pi rad`
The amplitude is same at both POINTS, HENCE amplitude different is zero.


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