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A planet has mass `1//10` of that of earth, while radius is `1//3` that of earth. If a person can throw a stone on earth surface height of 90m, then he will be able to throw the stone on that planet to a heightA. `90m`B. `40m`C. `100m`D. `45m` |
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Answer» Correct Answer - C Acceleration due to gravity `g=(GM)/(R^(2))` `:. (g_(plan et))/(g_(earth))=(M_(plan et))/(M_(earth)).((R_("earth"))/(R_("planet")))^(2)=1/10xx(3/1)^(2)=9/10` If a stone is thrown with velocity `u` from the surface of the planet then maximum height `H=(u^(2))/(2g) implies (H_(plan et))/(H_(earth))=(g_(earth))/(g_(plan et))` `implies H_(plan et) =10/9xxH_(earth)=10/9xx90=100 meter` |
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