1.

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms^(-1) , the escape velocity from the surface of the planet would be .......

Answer»

`1.1 KMS^(-1)`
`11 kms^(-1)`
`110 kms^(-1)`
`0.11 kms^(-1)`

Solution :`implies` Escape speed on earth `v_e = sqrt((2GM_e)/R_e)`
Escape speed on planet `v_p = sqrt((2GM_p)/R_p)`
but `M_p = 10 M_e and R_p = R_e/10`
`:. v_p =sqrt((2G(10M_e))/(R_e/10))= sqrt((100xx2GM_e)/R_e)`
`:. v_p = 10 XX v_e = 10 xx 11 = 110 kms^(-2)`


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