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A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms^(-1) , the escape velocity from the surface of the planet would be ....... |
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Answer» `1.1 KMS^(-1)` Escape speed on planet `v_p = sqrt((2GM_p)/R_p)` but `M_p = 10 M_e and R_p = R_e/10` `:. v_p =sqrt((2G(10M_e))/(R_e/10))= sqrt((100xx2GM_e)/R_e)` `:. v_p = 10 XX v_e = 10 xx 11 = 110 kms^(-2)` |
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