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A planet of mass `m` revolves in elliptical orbit around the sun of mass `M` so that its maximum and minimum distance from the sun equal to `r_(a)` and `r_(p)` respectively. Find the angular momentum of this planet relative to the sun.A. `L=msqrt((GMr_(p)r_(a))/((r_(p)+r_(a))))`B. `L=msqrt((2GMr_(p)r_(a))/((r_(p)+r_(a))))`C. `L=Msqrt((GMr_(p)r_(a))/((r_(p)+r_(a))))`D. `L=Msqrt(((r_(p)+r_(a)))/(GMr_(p)r_(a)))` |
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Answer» Correct Answer - B From conservation of energy `-(GMm)/(r_(p))+1/2mv_(p)^(2)=(-GMm)/(r_(a))+1/2mv_(a)^(2)` `L=mv_(p)r_(p)=mv_(a)r_(a)` |
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