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A planet revolves around sun in an elliptical orbit of eccentricity .e. . If .T. is the time period of the planet then show that the time spent by the planet between the end of the minor axis and close to sun is T (1/4-(e)/(2pi)) |
Answer» SOLUTION :`(dA)/(DT) ` = CONSTANT t , `(t_(AB))/(T) = (("AREA")"SAB")/("(Area) ellipse")=((piab)/(4)-1/2b(""ea))/(piab)` |
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