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A planetof massm movesin a ellipticalorbitaroundan unknownstarof massM suchthatitsmaximuman minimumdistances fromthe starare equaltor_1 and R_2respectively. Theangularmomentumof theplanetrelativetothe centreof thestar is |
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Answer» `m sqrt((2GM r_1 r_2)/(r_1 +r_(2)))` ACCORDING to theof conservationof ANGULARMOMENTUM ` mv _1r_1 = mv _2 r_2 ` ` impliesv_2 = (v_1r_1)/(r_2)` FROMTHE lawof conservationof totalmechanicalenergy . `(-GMM)/(r_1)+(1)/(2)mv _1^(2) =-(GMm)/(r_2)+(1)/(2) mv_(2)^(2)` .... (ii ) FromEqs.(i )and (ii )we get `V_1 =sqrt((2Gmr_2)/((r_1 +r_2)r_1)` Angularmomentum, ` L = mv _1 r_1 = m (sqrt((2GMr_2)/((r_1+r_2)r_1)))xxr_1` ` L= m sqrt((2GMr_1 r_2)/(r_1 +r_2))` |
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