InterviewSolution
Saved Bookmarks
| 1. |
A plastic rod of length 2.2m and radius 3.6 mm carries a negative charge of `3.8xx10^(-7) C` spread uniformly over its surface. What is the electric field near the mid-point of the rod, at a point on its surface? |
|
Answer» Here, l = 2.2m, `r = 3.6 mm = 3.6xx10^(-3)m`. `q = -3.8xx10^(-7)C.E = ?` Linear charge density, `lambda = (q)/(1) = (-3.8xx10^(-7))/(2.2)` `=-1.73xx10^(-7) Cm^(-1)` As `E = (lambda)/(2pi in_(0) r) = (2 lambda)/(4pi in_(0) r)` `:. E = (2(-1.73xx10^(-7)) xx9xx10^(9))/(3.6xx10^(-3))` `= -8.6xx10^(5) N//C` |
|