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A plastic scoop of mass 12g and density 0.6g/cc floats in water. How much mass is put inside the scoop to make it sink? |
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Answer» We know that, Weight of displaced water = weight of schoop+ mass kept in the schoop. Therefore, ΡwVg=Mg, Here M is the mass of the schoop + added mass=(12 +m)g, Ρw= density of water =1gm/cc:, ΡwVg = (12+m), So, 12+m =1xV……….. (i): V= VOLUME of water displaced = volume of the scoop=12/ density=12/0.6 =20cc: So, m=20-12=8gm Therefore, 8 gm of weight to be PLACE in scoop to SINK in water is the ANSWER. |
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