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A player caught a cricket ball of m ass 150 g moving at a rate of 20 m //s^(- 1) . If the catching process is com pleted in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to ..... |
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Answer» Solution :The forceof the blowexertedby the ball onthehandof theplayer= thechangein momentumof the ball `F=m(v_(1) -v_(2))/( t )` `=(0.15(20 - 0))/( 0.1)` `F= 30 N` `m =150 g = 0.150 kg` `v_(1)= 20 m//s` `v_(2) =0` `t=0.1s` |
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