1.

A player caught a cricket ball of m ass 150 g moving at a rate of 20 m //s^(- 1) . If the catching process is com pleted in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to .....

Answer»

0.3 N
3 N
30 N
300 N

Solution :The forceof the blowexertedby the ball onthehandof theplayer= thechangein momentumof the ball
`F=m(v_(1) -v_(2))/( t )`
`=(0.15(20 - 0))/( 0.1)`
`F= 30 N`
`m =150 g = 0.150 kg`
`v_(1)= 20 m//s`
`v_(2) =0`
`t=0.1s`


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