A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. The cathcing process is completed in 0.1 second. What is the force exerted by the ball on the hand of the player?

A player caught a cricket ball of mass 150 g moving at a rate of 20 m/

1.	A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. The cathcing process is completed in 0.1 second. What is the force exerted by the ball on the hand of the player?
Answer» 15 N 20 N 30 N 40N Solution :Impulse = Change in MOMENTUM of `F xx t= m(v-0)` `Fxx0.1= 150xx10^(-3)[20-0]` `THEREFORE F= (150xx10^(-3)xx20)/(0.1)= 30N`