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A player initially at rest throws a ball with an initial speed `u = 19.5 m//s` at an angle `theta = sin^(-1) ((12)/(13))` to the horizontal. Immediately after throwing the ball he starts running to catch it. He runs with constant acceleration (a) for first 2 s and thereafter runs with constant velocity. He just manages to catch the ball at exactly the same height at which he threw the ball. Find ‘a’. Take `g = 10 m//s^(2)`. Do you think anybody can run at a speed at which the player ran? |
Answer» Correct Answer - `a = 5.19 m//s^(2)` |
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